Intuition
You are given a 0-indexed array of positive integers w where w[i] describes the weight of the ith index.
You need to implement the function pickIndex(), which randomly picks an index in the range [0, w.length - 1] (inclusive) and returns it. The probability of picking an index i is w[i] / sum(w).
For example, if w = [1, 3], the probability of picking index 0 is 1 / (1 + 3) = 0.25 (i.e., 25%), and the probability of picking index 1 is 3 / (1 + 3) = 0.75 (i.e., 75%).
Example 1:
Input [“Solution”,”pickIndex”] [[[1]],[]] Output [null,0]
Explanation Solution solution = new Solution([1]); solution.pickIndex(); // return 0. The only option is to return 0 since there is only one element in w. Example 2:
Input [“Solution”,”pickIndex”,”pickIndex”,”pickIndex”,”pickIndex”,”pickIndex”] [[[1,3]],[],[],[],[],[]] Output [null,1,1,1,1,0]
Explanation Solution solution = new Solution([1, 3]); solution.pickIndex(); // return 1. It is returning the second element (index = 1) that has a probability of 3/4. solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 1 solution.pickIndex(); // return 0. It is returning the first element (index = 0) that has a probability of 1/4.
Since this is a randomization problem, multiple answers are allowed. All of the following outputs can be considered correct: [null,1,1,1,1,0] [null,1,1,1,1,1] [null,1,1,1,0,0] [null,1,1,1,0,1] [null,1,0,1,0,0] …… and so on.
Constraints:
1 <= w.length <= 104 1 <= w[i] <= 105 pickIndex will be called at most 104 times.
Approach
Culmulative Sum : creating buckets Binary Search : To find the best buckets
ref: https://www.youtube.com/watch?v=7x7Ydq2Wfvw&t=382s&ab_channel=CrackingFAANG
Complexity
-
Time complexity:
-
Space complexity:
Code
class Solution(object):
def __init__(self, w):
"""
:type w: List[int]
"""
self.prefix_sums =[]
total =0
#Culmulative Sum
for weight in w:
total += weight
self.prefix_sums.append(total)
self.total = total
def pickIndex(self):
"""
:rtype: int
"""
#[1,2,4] -->(CulmulativeSum) [1,3,7] --> 4
target =random.uniform(0, self.total)
# binary search
left = 0
right = len(self.prefix_sums)
while left <right:
mid = (left + right) //2
if self.prefix_sums[mid] < target:
left = mid + 1
else:
right = mid
return left
#INIT --> Time O(N), Store: O(N)
#pickIndex --> Time: log(N) bc binary search, Store O(1) bc target, left and right
# Your Solution object will be instantiated and called as such:
# obj = Solution(w)
# param_1 = obj.pickIndex()